A study was conduced to find out the concentration of sulphur dioxide in the air in parts per million (ppm) of a certain city. The data obtained for 30 days is as follow:
`{:("0.03 0.08 0.08 0.09 0.04 0.17"),("0.16 0.05 0.02 0.06 0.18 0.20"),("0.11 0.08 0.12 0.13 0.22 0.07"),("0.08 0.01 0.10 0.06 0.09 0.18"),("0.11 0.07 0.05 0.07 0.01 0.04"):}`
You were asked to prepare a frequency distribution table, regarding the concentration of sulphur dioxide in the air in parts per million of a certain city for 30 days. Using this table, find the probability of the concentration of sulphur dioxide in the interval 0.12-0.16 on any of these days.

Options

A. `(2)/(3)`
B. `(4)/(15)`
C. `(2)/(15)`
D. `(1)/(15)`

Answer

D

Explanation

Now, we prepare a frequency distribution table
`{:("Interval"," Frequency"),("0.01-0.04"," 5"),("0.04-0.08"," 11"),("0.08-0.12"," 7"),("0.12-0.16"," 2"),("0.16-0.18"," 4"),("0.20-0.24"," 1"),(" Total"," 30"):}`
The total number of days for data, to prepare sulphur dioxide, n(S) = 30
The frequency of the sulphur dioxide in the interval `0.12-0.16,n(E)=2`
`therefore" Required probability"=(n(E))/(n(S))=(2)/(30)=(1)/(15)`