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10 packets of suger each marked 1 kg act...

10 packets of suger each marked 1 kg actually contained the following weights 0.6 kg, 1.050 kg, 1.1 kg, -0.98 kg, 0.92 kg, 1.3 kg, 1.4 kg, 1.00 kg, 0.94 kg, 1.03 kg. Out of these packets, one packet is chosen at random, what is the probability that the chosen packet contain
(i) more than 1 kg sugar,
(ii) 1 kg sugar,
(iii) less than 1 kg sugar?

Text Solution

Verified by Experts

The correct Answer is:
`(i)(1)/(2)(ii)(1)/(10)(iii)(2)/(5)`
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