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If y = f(x) = (x+2)/(x-1) , x ne1 , then...

If y = f(x) = `(x+2)/(x-1) , x ne1` , then show that x = f(y) .

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`f(x)=(x+2)/(x-1)`
`implies" "f(y)=(y+2)/(y-1)`
`implies" "f(y)=((x+2)/(x-1))/((x+2)/(x-1))-1" "(becausey=(x+2)/(x=1))`
`=((x+2)+2(x-1))/((x+2)-(x-1))`
`=(3x)/(3)=x.`
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