If `A={(-1,),1)}` find `AxxAxxA.`

Explanation

To find \( A \times A \times A \) where \( A = \{ -1, 1 \} \), we will follow these steps:

### Step 1: Find \( A \times A \)
The Cartesian product \( A \times A \) consists of all ordered pairs where the first element is from the first set \( A \) and the second element is from the second set \( A \).

- The elements of \( A \) are \( -1 \) and \( 1 \).
- Therefore, the pairs are:
- \( (-1, -1) \)
- \( (-1, 1) \)
- \( (1, -1) \)
- \( (1, 1) \)

So, we have:
\[ A \times A = \{ (-1, -1), (-1, 1), (1, -1), (1, 1) \} \]

### Step 2: Find \( A \times A \times A \)
Now we need to find \( A \times A \times A \). This means we will take the Cartesian product of \( A \times A \) with \( A \).

Each element of \( A \times A \) will be paired with each element of \( A \):
- For \( (-1, -1) \):
- \( (-1, -1, -1) \)
- \( (-1, -1, 1) \)

- For \( (-1, 1) \):
- \( (-1, 1, -1) \)
- \( (-1, 1, 1) \)

- For \( (1, -1) \):
- \( (1, -1, -1) \)
- \( (1, -1, 1) \)

- For \( (1, 1) \):
- \( (1, 1, -1) \)
- \( (1, 1, 1) \)

Combining all these, we get:
\[ A \times A \times A = \{ (-1, -1, -1), (-1, -1, 1), (-1, 1, -1), (-1, 1, 1), (1, -1, -1), (1, -1, 1), (1, 1, -1), (1, 1, 1) \} \]

### Final Answer:
\[ A \times A \times A = \{ (-1, -1, -1), (-1, -1, 1), (-1, 1, -1), (-1, 1, 1), (1, -1, -1), (1, -1, 1), (1, 1, -1), (1, 1, 1) \} \]