The Cartesian product `A xxA` has 9 elements among which are found `(1," "0)" "a n d" "(0," "1)` . Find the set A and the remaining elements of `A xxA` .

Answer

N/a

Explanation

`{(1,0),(0,1)} sube A xx A`
`therefore A={-1,0,1}`
Now `AxxA={-1,0,1}xx{-1,0,1}`
=`{(-1,-1),(-1,0),(-1,1),(0,-1), (0,0),(0,1),(1,-1),(1,0),(1,1)}`
Remaining elements of `AxxA ={(-1,-1),(-1,1),(0,-1),(0,0),(1,-1),(1,0),(1,1)}`