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Solve the equation:x^2-x+2=0...

Solve the equation:`x^2-x+2=0`

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The correct Answer is:
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Given equation is `-x^(2) +x-2=0`
Here, `A=-1, B= 1, C = -2`
Discriminant `D=B^(2)-4AC= (1)^(2)-4xx(-1)xx(-2)`
`" "= 1- 8=7`
`therefore" "x=(-Bpmsqrt(D))/(2A) =(-1pmsqrt(-7))/(2xx(-1))`
`" '=(-(1pmsqrt(-7) ))/(2xx-1)=(1pm isqrt(7 ))/(2)`
Therefore, solutions of equation are `x =(1 pmisqrt(7))/(2) `
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