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How many numbers between 6000 and 7000 a divisible by 5 which can be formed with the digits 5,6,7 and 9?

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To solve the problem of finding how many numbers between 6000 and 7000 can be formed using the digits 5, 6, 7, and 9 that are divisible by 5, we can follow these steps: ### Step 1: Understand the constraints We need to form a four-digit number that: - Lies between 6000 and 7000 - Ends with the digit 5 (to be divisible by 5) - Starts with the digit 6 (to be between 6000 and 7000) ### Step 2: Fix the first and last digits Since the number must start with 6 and end with 5, we can represent the number as: \[ 6 \_ \_ 5 \] ### Step 3: Determine the middle digits The two middle digits can be filled with any of the available digits: 5, 6, 7, or 9. Since we are allowed to repeat digits, we can choose any of these digits for both positions. ### Step 4: Calculate the combinations for the middle digits For each of the two middle positions, we have 4 choices (5, 6, 7, or 9). Therefore, the number of combinations for the two middle digits is: \[ 4 \times 4 = 16 \] ### Step 5: Conclusion Thus, the total number of four-digit numbers between 6000 and 7000 that can be formed with the digits 5, 6, 7, and 9, and are divisible by 5 is: \[ \text{Total Numbers} = 16 \] ### Final Answer The total number of such numbers is **16**. ---
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NAGEEN PRAKASHAN-PERMUTATION AND COMBINATION -Exercise C
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