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In how many ways can a team of 11 players be selected from 14 players?

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To solve the problem of selecting a team of 11 players from a pool of 14 players, we will use the concept of combinations. The number of ways to choose \( R \) objects from \( N \) objects is given by the formula: \[ NCR = \frac{N!}{R!(N-R)!} \] ### Step-by-Step Solution: 1. **Identify the values of N and R**: - Here, \( N = 14 \) (total players) and \( R = 11 \) (players to be selected). 2. **Use the combination formula**: - We need to calculate \( 14C11 \). - According to the formula: \[ 14C11 = \frac{14!}{11!(14-11)!} = \frac{14!}{11! \cdot 3!} \] 3. **Simplify the factorials**: - We can simplify \( 14! \) as follows: \[ 14! = 14 \times 13 \times 12 \times 11! \] - Therefore, substituting back into the equation: \[ 14C11 = \frac{14 \times 13 \times 12 \times 11!}{11! \cdot 3!} \] 4. **Cancel out the common \( 11! \)**: - The \( 11! \) in the numerator and denominator cancels out: \[ 14C11 = \frac{14 \times 13 \times 12}{3!} \] 5. **Calculate \( 3! \)**: - \( 3! = 3 \times 2 \times 1 = 6 \). 6. **Substitute \( 3! \) back into the equation**: \[ 14C11 = \frac{14 \times 13 \times 12}{6} \] 7. **Perform the multiplication**: - First, calculate \( 14 \times 13 \times 12 \): \[ 14 \times 13 = 182 \] \[ 182 \times 12 = 2184 \] 8. **Divide by 6**: \[ 14C11 = \frac{2184}{6} = 364 \] 9. **Final answer**: - Therefore, the number of ways to select 11 players from 14 players is \( 364 \). ### Summary: The total number of ways to select a team of 11 players from 14 players is **364**.
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NAGEEN PRAKASHAN-PERMUTATION AND COMBINATION -Exercise F
  1. If .^(16)C(r) = .^(16)C(r+6), then find .^(5)C(r).

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  2. Determine n if (i) ^2n C2:^n C2=12 :1 (ii) ^2n C3:^n C3=11 :1

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  3. Determine n if (i) ^2n C2:^n C2=12 :1 (ii) ^2n C3:^n C3=11 :1

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  4. Determine n if (i) ^2n C2:^n C2=12 :1 (ii) ^2n C3:^n C3=11 :1

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  5. If .^(15)C(r): .^(15)C(r-1) = 1:5, then find r.

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  6. If .^(n-1)P3 :^(n+1)P3 = 5 : 12, find n.

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  7. If .^(n)P(r) = 720 and .^(n)C(r) = 120, then find r. = (5 xx 4 xx 3...

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  8. If ^(n+1)C(r+1): ^nCr: ^(n-1)C(r-1)=11:6:2 find the values of n and r.

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  9. If .^(n)C(4),.^(n)C(5), .^(n)C(6) are in A.P., then find the value of ...

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  10. If alpha=\ \ ^m C2,\ then find the value of \ ^(alpha)C2dot

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  11. In how many ways can a team of 11 players be selected from 14 players?

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  12. In how many ways 2 persons can be selected from 4 persons?

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  13. In how many ways can a person invites his 2 or more than 2 friends out...

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  14. In how many ways can 11 players be selected from 14 players if (i) a...

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  15. In how many ways can 5 subjects be chosen from 9 subjects if three sub...

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  16. In how many ways can 4 books be chosen from 12 books if (i) there is...

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  17. There are 5 black and 6 red bills in a bag. Find one number of ways in...

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  18. In 25 cricket players, there are 10 batsmen, 9 bowlers, 4 all-rounders...

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  19. There are 8 math's books and 6 science books in a almirah. In how many...

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  20. There are 3 parts A,B and C in a question paper of Math's, which inclu...

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