Home
Class 11
MATHS
Find the locus of a point whose each poi...

Find the locus of a point whose each point is equidistant from the points A(2,3,-4) and B(-1,2,3).

Text Solution

Verified by Experts

The correct Answer is:
N/a
Let P(x,y,z) be any point on the path.
Given that
PA=PB
`implies PA^(2)=PB^(2)`
`implies (x-2)^(2)+(y-3)^(2)+(z+4)^(2)`
`=(x+1)^(2)+(y-2)^(2)+(z-3)^(2)`
` implies x^(2)-4x+4+y^(2)-6y+9+z^(2)+8z+16`
`=x^(2)+2x1+y^(2)-4y+4+z^(2)-6z+9`
`implies 6x+2y-14z-15=0`.
Promotional Banner

Topper's Solved these Questions

  • INTRODUCTION OF THREE DIMENSIONAL GEOMETRY

    NAGEEN PRAKASHAN|Exercise Exercise 12 A|5 Videos

  • INTRODUCTION OF THREE DIMENSIONAL GEOMETRY

    NAGEEN PRAKASHAN|Exercise Exercise 12 B|18 Videos

  • CONIC SECTION

    NAGEEN PRAKASHAN|Exercise Miscellaneous Exercise|8 Videos

  • LIMITS AND DERIVATIVES

    NAGEEN PRAKASHAN|Exercise Miscellaneous Exercise|30 Videos

Similar Questions

Explore conceptually related problems

Find the locus of the point which is equidistant from the points A(0,2,3) and B(2,-2,1)

Find the locus of a point which is equidistant from the points (-1,2,3) and (3,2,1)

Find the locus of the point which is equidistant from the points A(0,2,3) and (2,-2,1) .

Find the locus of the point which is equidistant from the points (1,-2,3) and (-3,4,2).

Find the locus of the points which are equidistant from the points (1,2,3) and (3,2,11).

Determined the equation to the locus of the point which is equidistant from the points ( 2 , - 2 , - 4) and ( - 3 , 1 , 2) .

Find a point on theyaxis which is equidistant from the points A(6,5) and B(-4,3)

The locus of the point which is equidistant from the points (2, -2, 1) and (0, 2, 3) is

Find the value of k, if the point P(2,4) is equidistant from the points A(5,k) and B(k,7).

Find the locus of a point which is equidistant from (1,3) and x -axis.