Find the mean deviation about the median for the data : `36 , 72 , 46 , 42 , 60 , 45 , 53 , 46 , 51 , 49`

Explanation

Taking the given terms in ascending order

Here `N=10` (even)
`:.` Median `M=(N/2 "th term" +(N/2+1) "th term")/2`
`=(10/2 "th term" +(10/2+1) "th term")/2`
`=(5 "th term" + "6 th term")/2`
`=(46+49)/2=47.5`
Now mean deviatin `=(sum|x_(i)-M|)/N=70/10=7`