Find the probability of `53` Sundays in an ordinary year.

Options

A. `1//7`
B. `2//7`
C. `3//7`
D. `4//7`

Answer

A

Explanation

No. of days in an ordinary year `=365`
There are `52` weeks and one day in `365` days.
Now there are `52` Sundays in `52` weeks.
Remaining one day can be any day out of `7` week days.
`:.` Total possible outcomes `=7`
No. of favourable outcomes for Sunday `=1`
`:.` Probability of `53` Sundays in an ordinary year `=1/7`.