Find the probability of getting 5 at least once in there throws of a dice.

Answer

N/a

Explanation

Probability of getting 5 in a throw of a dice `=1/6`
Probability of not gettng 5 in a throw of a dice
`=1-1/6=5/6`
Similarly probability of not getting 5 in 2nd throw of a dice`=5/6`
and probability of not getting 5 in 3rd throw of a dice `=5/6`
Now probability of not getting 5 in three throws of a dice `=5/6xx5/6xx5/6=125/216`
`implies` Probability of getting 5 at least once in three throws of a dice `=1-125/256=91/216`