Find the probability of getting a sum at least 5 on three dice in one throw three dice.

Answer

N/a

Explanation

In one throw of thre dice
`n(S)=6xx6xx6=216`
Let `E=` event of getting a sum of numbers 3 or 4
`={(1,1,1),(1,1,2),(1,2,1),(2,1,1)}`
`implies n(E)=4`
Now `P(E)=(n(E))/(n(S))=4/216=1/54`
`:.P(barE)=` probability of getting a sum of numbers at least 5
`=1-P(E)=1-1/54=53/54`