A coin a tossed twice, that is the probability that at least one tail occurs?

Answer

N/a

Explanation

In two tosses of a coin
Sample space `S={HH,HT,TH,"TT"}`
`impliesn(S)=4`
Let `E=` event of gettng at least one tail
`{HT,TH,"TT"}`
`impliesn(E)=3`
Now probability of event `E`
`P(E)=(n(E))/(n(S))=3/4`