In a certain lottery 10,000 tickets are sold and ten equal prizes are awarded. What is the probability of not getting a prize if you buy (a) one ticket (b) two tickets (c) 10 tickets.

Answer

N/a

Explanation

Total tickes `=10,000`
Total prizes `=10`
No. of tickets without prize `=1000-10`
`=9990`
(a) on buying one ticket
Probability of not getting a prize `=(.^(9990)C_(1))/(.^(10000)C_(1))`
`=9990/10000`
`=999/1000`
(b) on buying two tickets,
Probability of not getting a prize `=(.^(9990)C_(2))/(.^(10000)C_(2))`
(c) On buying 10 tickets
Probability of not getting a prize `=(.^(9990)C_(10))/(.^(10000)C_(10)`