Find the minimum magnification of a microscope, whose objective's numerical apertune is `sin alpha = 0.24`, at which the resolving power of the objective is totally employed if the diameter of the eye's pupil is `d_(0) = 4.0mm`.

Determine the minimum multiplication of a telescope with diameter of objetive D = 5.0cm with which th resolving power of the objective is totally employed if the diameter of the eye's pupi is d_(0) = 4.0mm .

A telescope, whose objective lens has an apertune of 1 mm for the wavelength of light 500 A, then limiting resolving power of the telescope is

There is a microscope whose objective's numerical aperture is sin alpha = 0.24 , where alpha is the half-angle subtended by the objective's rim. Find the minimum spearation resolved by this microscope when an object is illuminated by light with wavelength lambda = 0.55 mu m .

A microscople has numberical apertune sin alpha = 0.12 , where alpha is the aperture angle subtended by the entrance pupil of the microscope. Assuming the diameter of an eye's pupil to be equal to d_(0) = 4.0 mm determine the microscope magnification at which (a) the diameter of the beam of light coming from the microscope is equal to the diameter of the eye's pupil, (b) the illuminance of the image on the retina is independent of magnification (consider the case when the beam of light passing through teh sysytem ''microscope-eye'' is bounded by the mounting of the objective).

The numerical aperture of a microscope is 0.31. If the wavelength of light used in 600 nm, calculate the resolving power of the microscope.

Find the magnifying power of a compound microscope whose objective has a focal power of 100D and eye piece has a focal power of 16D when the object is placed at a distance of 1.1cm from the objective. Assume that the final image is formed at the least distance of distinct vision (25cm)

Calculate the resolving power of a microscope if its numerical aperture is 0.12 and wavelength of light used is 6000 Å .

The angular magnification of a telescope is 300 What should be the diameter of the objective, if our eyes at the eye ring, are just able to collect all the light refracted from the objective. Take diameter of pupil of eye = 3mm .