The magnitude of the equatorial magnetic field due to a bar magnet of length 2 cm at a distance of 1lm from its mid-point is (magnetic moment of the bar magnet is 0.60 A m)

Options

A. `5.0xx10^(-5)` T
B. `6.0xx10^(-8)` T
C. `7.0xx10^(-7)` T
D. `8.0xx10^(-8)` T

Answer

B

Explanation

Magnetic field of equatorial point is
`B_(E)=(mu_(0)m)/(4pir^(3))`
Here, `=(mu_(0))/(4pi)=10^(-7), r` = 1 m and `m` = 0.60 A `m^(2)`
`therefore" "B_(E)=(10^(-7)xx0.60)/((1)^(3))=6.0xx10^(-8)` T