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The torque and magnetic potential energy...

The torque and magnetic potential energy of a magnetic dipole in most stable position in a uniform magnetic field `vec(B)` having magnetic moment `vec(m)` will be

A

`-mB,zero`

B

`mB,zero`

C

`zero,mB`

D

`zero,-mB`

Text Solution

Verified by Experts

The correct Answer is:
D

Torque, `"Torque", vec(tau)=vec(m)xxvec(B)=mB sin theta`
and magnetic potential energy `U_(m)=vec(m).vec(B)=mB sin theta`
`theta=0^(@)` the dipole will be in most stable position
`pi=mB sin theta=mB sin 0^(@)=0`
`and U_(m)=-mB cos theta=-mBcos 0^(@)=-mB`
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