Home
Class 12
PHYSICS
A magnetising field of 1500 A//m produce...

A magnetising field of `1500 A//m` produces a flux of `2*4xx10^-5` weber in a bar of iron of cross-sectional area `0*5cm^2`. Calculate the permeability and susceptibility of the iron bar used.

A

245

B

250

C

252

D

255

Text Solution

Verified by Experts

The correct Answer is:
D
`Here, H=1500Am^(-1), phi=2.4xx10^(-5)"weber"`
`A=0.5cm^(2)=0.5xx10^(-4)m^(2)`
`therefore B=(phi)/(A)=(2.4xx10^(-5))/(0.5xx10^(-4))=4.8xx10^(-1)T`
`and mu=(B)/(H)=(4.8xx10^(-1))/(1500)=3.2xx10^(-4)`
So relative permeability
`mu_(r)=(mu)/(mu_(0))=(3.2xx10^(-4))/(4pixx10^(-7))=0.255xx10^(23)=255`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • MAGNETISM AND MATTER

    NCERT FINGERTIPS|Exercise Magnetic Properties Of Materials|26 Videos

  • MAGNETISM AND MATTER

    NCERT FINGERTIPS|Exercise Permanent Magnets And Electromagnets|4 Videos

  • MAGNETISM AND MATTER

    NCERT FINGERTIPS|Exercise The Earth'S Magnetism|19 Videos

  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

  • MOVING CHARGES AND MAGNETISM

    NCERT FINGERTIPS|Exercise Assertion And Reason|15 Videos

Similar Questions

Explore conceptually related problems

A magnetic field of 1600Am^-1 produces a magnetic flux of 2*4xx10^-5 weber in a bar of iron of cross section 0*2cm^2 . Calculate permeability and susceptibility of the bar.

A magneting field of 1600 Am^(-1) produces a magnetic flux of 2.4xx10^(-5) wb in an iron bar of cross-sectional area 0.2cm^(2) .Calculate the permeability and susceptibility of the bar.

Knowledge Check

  • If a magnetising field of 1600 A//m produces a magnetic flux of 14xx10^(-5) Wb in an iron bar of cross-sectional area 0.2 cm^(2) . Then,

    A
    magnetic permeability of iron rod is around 1000
    B
    magnetic susceptibility is very larger than unity
    C
    magnetic susceptibility is 340
    D
    None of the above

  • A magnetising field of 1600 A/m produces a magnetic flux of 2.4 xx 10^(-5)Wb in a bar of iron of cross section 0.2"cm"^(2) . Then permeability of the bar is the equator

    A
    `7.5 xx 10^(-4) T A^(-1) m`
    B
    `7.5 xx 10^(-4)T A m^(-1)`
    C
    `7.5 xx 10^(-3)T A m`
    D
    `7.5 xx 10^(-2) T A m^(-1)`

  • A magnetising field of 1600 Am^(-1) produces a magnetic flux 2.4 xx 10 ^(-5) weber in an iron bar of cross-sectional area 0.2 cm^(2). The susceptibility of the iron bar will be

    A
    1788
    B
    1192
    C
    596
    D
    298

    • Similar Questions

    Explore conceptually related problems

    A magnetising field of 1600 Am^(-1) produces a magnetic flux 2.4 xx 10^(-5) weber in an iron bar of cross-sectional area 0.2 cm^(2) . The susceptibility of the iron bar will be

    The magnetic field of 20CGS units produces of a flux of 2400 CGS units in a bar of cross section 0.2cm^(3) Calculate the (i) permeability and (ii) susceptibility of the bar.

    A magnetising field fo 1000 A/m produces a magnetics flux of 2.4 xx10^(-5) Wb in an iron bar of cross sectional area 0.3 cm^(2) what is the magnetic permeability of the iron bar ?

    A magnetising field of 5000 A//m produces a magnetic flux of 5xx10^(-5) weber in an iron rod. If the area of cross section of the rod is 0.5 cm^(2) , then the permeability of the rod will be

    A magnetising field of 1600 A m^(-1) produces a magnetic flux of 2.4 xx 10^(-5) Wb in an iron bar of cross-sectional area 0.2 c m^(2) . The susceptibility of an iron bar is

    Home
    Profile