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A magnetising field of 1500 A//m produce...

A magnetising field of `1500 A//m` produces a flux of `2*4xx10^-5` weber in a bar of iron of cross-sectional area `0*5cm^2`. Calculate the permeability and susceptibility of the iron bar used.

A

245

B

250

C

252

D

255

Text Solution

Verified by Experts

The correct Answer is:
D
`Here, H=1500Am^(-1), phi=2.4xx10^(-5)"weber"`
`A=0.5cm^(2)=0.5xx10^(-4)m^(2)`
`therefore B=(phi)/(A)=(2.4xx10^(-5))/(0.5xx10^(-4))=4.8xx10^(-1)T`
`and mu=(B)/(H)=(4.8xx10^(-1))/(1500)=3.2xx10^(-4)`
So relative permeability
`mu_(r)=(mu)/(mu_(0))=(3.2xx10^(-4))/(4pixx10^(-7))=0.255xx10^(23)=255`
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