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A magnetizing field of 2xx10^(3)Am^(-1) ...

A magnetizing field of `2xx10^(3)Am^(-1)` produces a magnetic flux density of `8piT` in an iron rod. The relative permeability of the rod will be

A

`10^(2)`

B

1

C

`10^(4)`

D

`10^(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
`"Here", H=2xx10^(3)Am^(-1)`
`B=8pi T, mu_(0)=4pixx10^(-7)`
`"Since", mu_(r)=(mu)/(mu_(0))=(muH)/(mu_0H)=(B)/(mu_(0)H)=(8pi)/(4pixx10^(-7)xx2xx10^(3))=10^(4)`
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