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In a quadrilateral ABCD, which is not a ...

In a quadrilateral ABCD, which is not a trapezium, it is known that `angle DAB=angle ABC=60^(2)`. Moreover `angle CAB = angle CBD`. Then

A

`AB=BC+CD`

B

`AB=AD+CD`

C

`AB=BC+AD`

D

`AB=AC+AD`

Text Solution

Verified by Experts

The correct Answer is:
C
Construction : complete the equilateral `DeltaAPB`

`DeltaABC~DeltaBPD`
`:. (X-a)/X=b/XrArr A=a+b`
`AB=AD+BC`
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