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Suppose S(1)" and "S(2) are two unequal...

Suppose `S_(1)" and "S_(2)` are two unequal circles, AB and CD are the direct common tangents to these circles. A transverse common tangent PQ cuts AB in R and CD in S. If AB = 10, then RS is -

A

8

B

9

C

10

D

11

Text Solution

Verified by Experts

The correct Answer is:
C

`AR=PR=10-x` ltBRgt `PQ=10-2x`
`AB=CD=10`
`CD=CS+SD=y+SD`
`=y+SP+PQ`
`10=y+y+10-2x`
`RaRR y=x`
Now `RS=SP+PQ+QR`
`=y+10-2x+x`
`=10+y-x=10`
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