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If the radius of the drogen atom is 53 p...

If the radius of the drogen atom is 53 pm, the radius of the `He^(+)` ion is closest to :

A

108 pm

B

81 pm

C

27 pm

D

13 pm

Text Solution

Verified by Experts

The correct Answer is:
C
`r_(He^(+o))=r_(H)xx(n_(2))/Z`
`r_(He^(+))=53xx1/2=26.5` pm It is closest to 27 pm.
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