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The oxdidation number of sulphur is +4 i...

The oxdidation number of sulphur is +4 is

A

`H_(2)S`

B

`CS_(2)`

C

`Na_(2)SO_(4)`

D

`Na_(2)SO_(3)`

Text Solution

Verified by Experts

The correct Answer is:
d
`H_(2)S^(-2)`
`CS_(2)^(-2)`
`Na_(2)overset(+6)(SO)_(3)`
`Na_(2)overset(+4)(SO)_(3)`
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