At a constant pressure P, the plot of volume (V) as a function of temperature (T) for 2 moles of an ideal gas gives a straight line with a slope 0.328 L `K^(-1)`. The value of P (in atm) is closest to [Gas constant, R = 0.0821 L atm `mol^(-1)" "K^(-1)`]

Options

A. `0.25`
B. `0.5`
C. `1.0`
D. `2.0`

Answer

B

Explanation

`PV=nRT`
`rArr(V)/(T)=(nR)/(P)= "slope"`
`rArrP=(nR)/("slope")=(2xx0.0821)/(0.328)=0.5`