[" (ii) "sin3A+sin2A-sin A],[qquad =4sin A cos(A)/(2)cos(3A)/(2)]

sin3A+sin2A-sin A=4sin A*cos((A)/(2))*cos((3A)/(2))

Show that sin 3 A + sin 2A -sin A = 4 sin A cos (A)/(2) cos "" (3A)/( 2)

Prove that: \ sin3A+sin2A-sin A=4sin A cos (A/2)cos((3A)/2)

Prove that: (i) sin 3x+"sin" 2x-"sin" x = 4 sin x cos((x)/(2))cos((3x)/(2)) (ii) ("sin" 3x+"sin" x)"sin" x+(cos 3x-cos x)cos x=0.

Prove that : sin3A+ sin 2A- sinA= 4 sinA cos frac (A)(2) cos frac (3A)(2) .

Prove that sin 3x + sin 2x - sin x = 4 sin x cos ""(x)/(2) cos "" ( 3x )/(2)

sin 3x + sin 2x - sin = 4sin x cos "" x/2 cos "" (3x)/(2)

sin 3x + sin 2x - sin = 4sin x cos "" x/2 cos "" (3x)/(2)

sin 3x + sin 2x - sin = 4sin x cos "" x/2 cos "" (3x)/(2)

Prove that, sinA+sin2A+sin4A+sin5A= 4cos((A)/(2))cos((3A)/(2))sin3A .