" The line "y-x+3=0" is normal at the point "(3+(3)/(sqrt(2)),(3)/(sqrt(2)))" to the circle.Then the equation of "t

To which of the circles,the line y-x+3=0 is normal at the point (3+3sqrt(2),3sqrt(2)) is

To which of the circles, the line y-x+3=0 is normal at the point (3+3sqrt2, 3sqrt2) is

To which of the following circleS, the line y-x+3=0 is a normal at (3+(3)/(sqrt(2)), (3)/(sqrt(2))) ?

A beam of light is sent along the line x-y=1 , which after refracting from the x-axis enters the opposite side by turning through 30^0 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is (2-sqrt(3))x-y=2+sqrt(3) (2+sqrt(3))x-y=2+sqrt(3) (2-sqrt(3))x+y=(2+sqrt(3)) y=(2-sqrt(3))(x-1)

A circle C of radius 1 is inscribed in an equilateral triangle PQR . The points of contact of C with the sides PQ, QR, RP and D, E, F respectively. The line PQ is given by the equation sqrt(3) +y-6=0 and the point D is ((3sqrt(3))/(2), 3/2) The equation of circle C is : (A) (x-2sqrt(3))^2 + (y-1)^2 = 1 (B) (x-2sqrt(3))^2 + (y+1/2)^2 = 1 (C) (x-sqrt(3))^2 + (y+1)^2 = 1 (D) (x-sqrt(3))^2 + (y-1)^2 =1

Show that the equation of the normal to the ellipse (x^(2))/(25)+(y^(2))/(9)=1 at ((5)/(sqrt(2)),(3)/(sqrt(2))) is the line 5x-3y=8sqrt(2)

A circle C of radius 1 is inscribed in an equilateral triangle PQR . The points of contact of C with the sides PQ, QR, RP and D, E, F respectively. The line PQ is given by the equation sqrt(3) +y-6=0 and the point D is ((sqrt(3))/(2), 3/2) The equation of circle C is : (A) (x-2sqrt(3))^2 + (y-1)^2 = 1 (B) (x-2sqrt(3))^2 + (y+1/2)^2 = 1 (C) (x-sqrt(3))^2 + (y+1)^2 = 1 (D) (x-sqrt(3))^2 + (y-1)^2 =1

A beam of light is sent along the line x-y=1 , which after refracting from the x-axis enters the opposite side by turning through 30^0 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is (a) (2-sqrt(3))x-y=2+sqrt(3) (b) (2+sqrt(3))x-y=2+sqrt(3) (c) (2-sqrt(3))x+y=(2+sqrt(3)) (d) y=(2-sqrt(3))(x-1)

A beam of light is sent along the line x-y=1 , which after refracting from the x-axis enters the opposite side by turning through 30^0 towards the normal at the point of incidence on the x-axis. Then the equation of the refracted ray is (a) (2-sqrt(3))x-y=2+sqrt(3) (b) (2+sqrt(3))x-y=2+sqrt(3) (c) (2-sqrt(3))x+y=(2+sqrt(3)) (d) y=(2-sqrt(3))(x-1)