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`f(x)` and `g(x)` are two differentiable functions in `[0,2]` such that `f"(x)=g"(x)=0, f'(1)=2, g'(1)=4, f(2)=3, g(2)=9` then `f(x)-g(x)` at `x=3/2` is

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Let f(x)and g(x) be twice differentiable functions on [0,2] satisfying f''(x)=g''(x) , f'(1)=4 , g'(1)=6 , f(2)=3 and g(2)=9 . Then what is f(x)-g(x) at x=4 equal to ?

If f (x) and g (x) are twice differentiable functions on (0,3) satisfying, f ''(x) = g'' (x), f '(1) =4, g '(1) =6,f (2) = 3, g (2)=9, then f (1) -g (1) is

If f(x),g(x) be twice differentiable functions on [0,2] satisfying f''(x)=g''(x)f'(1)=2g'(1)=4 and f(2)=3g(2)=9 then f(x)-g(x) at x=4 equals (A) 0 (B) 10 (C) 8 (D) 2

If f(x),g(x) be twice differentiable function on [0,2] satisfying f''(x)=g''(x) , f'(1)=4 and g'(1)=6,f(2)=3,g(2)=9,then f(x)-g(x) at x=4 equals to:- (a) -16 (b) -10 (c) -8

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f(x) and g(x) are differentiable functions for 0 le x le 2 such that f(0)=5, g(0)=0, f(2)=8, g(2)=1 . Show that there exists a number c satisfying 0 lt c lt 2 and f'(c)=3g'(c) .

f(x) and g(x) are differentiable functions for 0 <= x <= 2 such that f(0) = 5, g(0) = 0, f(2)= 8,g(2) = 1. Show that there exists a number c satisfying 0 < c < 2 and f'(c)=3 g'(c).

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