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Evaluate ("Lim")(x->0)[1/(x^2)-1/(sin^2x...

Evaluate `("Lim")_(x->0)[1/(x^2)-1/(sin^2x)]` using LHospitals Rule or otherwise :

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  • Evaluate : Lim_( x to 0) (sin 4x)/( sin 2x)

    A
    2
    B
    4
    C
    6
    D
    8
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