mx-ny=m^(2)+n^(2);x+y=2m

Solve for x and y : mx- ny = m^(2) + n^(2) " " x - y = 2n

solve the following pair using cross multiplication method mx+ny=m^(2)+n^(2) and x+y=2m

Solve the following system of equations by method of cross-multiplication: mx-ny=m^(2)+n^(2),quad x+y=2m

Select a suitable identity and find the following products (mx^(2) + ny^(2))(mx^(2) + ny^(2))

Prove : int sin mx sin n x dx[ m^(2) != n^(2)] , = 1/2 [ (sin(m-n)x)/(m-n) - (sin (m+n)x)/(m+n) ] + c

If the are between y =mx^(2) and x= my^(2) (m gt 0 ) is (1)/(4) sq . Unit then the value of m is:

Number of integral values of m for which lines x+y+1=0,mx-m^(2)y+3=0 and 2mx-(2m-1)y+(3m+2)=0 are concurrent

Prove that the tangent to the parabola y^(2)=4ax at ((a)/(m^(2)),(2a)/(m)) is y=mx+(a)/(m)