" The equilibrium constant "(K_(p))" for the reaction "PCl_(5)(g)rightleftarrows PCl_(3)(

At a given temperature the equilibrium constant for the reaction PCl_(5) (g) Leftrightarrow PCl_(3)(g)+Cl_(2)(g) is 2.4 xx 10^(-3) . At the same temperature the equilibrium constant for the reaction PCl_(3) (g)+Cl_(2)(g) Leftrightarrow PCl_(5) (g)

The equilibrium constant (K_(p)) for the reaction, PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) is 16 . If the volume of the container is reduced to half of its original volume, the value of K_(p) for the reaction at the same temperature will be:

The equilibrium constant (K_(p)) for the reaction, PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) is 16 . If the volume of the container is reduced to half of its original volume, the value of K_(p) for the reaction at the same temperature will be:

Unit of equilibrium constant K_p for the reaction PCl_5(g) hArr PCl_3(g)+ Cl_2(g) is

For the reaction, PCl_(5)(g)to PCl_(3)(g)+Cl_(2)(g)

At a given temperature, the equilibrium constant for the reaction : PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) is 2.4xx10^(-3) . At the same temperature, the equilibrium constant for the reaction : PCl_(3)(g)+Cl_(2)(g) harr PCl_(5)(g) is :

1 mol PCl_(2)(g) is heated in a closed container of 2 litre capacity. If at equilibrium, the quantity of PCl_(5)(g) be 0.2 mol then calculate the value of equilibrium constant for the given reaction, PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g) .