A particle starts sliding down a frictionless inclined plane. If ` S_(n) ` is the distance travelled by it from time ` t = n-1 sec `, to `t = n sec`, the ratio ` (S_(n))/(s_(n+1))` is

A small block slides without friction down an iclined plane starting form rest. Let S_(n) be the distance traveled from time t = n - 1 to t = n . Then (S_(n))/(S_(n + 1)) is:

A small block slides without friction down an iclined plane starting form rest. Let S_(n) be the distance traveled from time t = n - 1 to t = n . Then (S_(n))/(S_(n + 1)) is:

A small cube falls from rest along a frictionless inclined plane. If this distance travelled between times t = n -1 and t = n be s_(n) then the value of (s_(n))/(s_(n)+1) is

A small block slides without friction down an inclined plane starting from rest. Lets s_n be the distance travelled from time t=n - 1 to t = n. Then (S_n)/(s_n+1) is:

If S=t^(n) , where n ne 0 , then velocity equal acceleration at time t=3 sec if : n=

A particle is moving on a straight line so that its distance s from a fixed point at any time t is proportional to t^n . If v be the velocity and 'a' the acceleration at any time , then (nas)/(n-1) equals

The velocity of a particle is given by vec(v) = 2hat(i)-hat(j)+2hat(k) in m//s for time interval t = 0 to t = 10 sec. If the distance travelled by the particle in given time interval 10n , find value of n is.

The velocity of a particle is given by vec(v) = 2hat(i)-hat(j)+2hat(k) in m//s for time interval t = 0 to t = 10 sec. If the distance travelled by the particle in given time interval 10n , find value of n is.

In an A.P. if a=2, t_(n)=34 ,S_(n) =90 , then n=

In an A.P. if a=2, t_(n)=34 ,S_(n) =90 , then n=