y=x^(n)+n^(x)+x^(x)+n^(n)

If x^(n) y^(n) =(x+y) ^(n),then (dy)/(dx)=

If x ^(n) y^(n) =( x+y ) ^(n),then (dy)/(dx)=

The curve x^(n)/a^(n) + y^(n)/b^(n) = 2 touches the line, x/a + y/b = 2 at the point,

If the arithmetic mean of x and y be (x^(n+1)+ y^(n+1))/(x^(n) + y^(n)) , then find n.

If |[x^(n-1), x^(n+1), x^(n+2)] ,[y^(n-1), y^(n+1), y^(n+2)], [z^(n-1), z^(n+1), z^(n+2)]|= (x-y)(y-z)(z-x)(x^(-1)+y^(-1)+z^(-1)) then n=

The HCF of x^(2) - y^(2), x^(3) - y^(3), …... x^(n) - y^(n) , where n in N is ………. .

Insert : Let (x^(n+1) + y^(n+1))/(x^(n) + y^(n)) be the geometric mean of x and y , find n.

Compute the product : (x^n -y^(-n))(x^n +y^(-n)) .