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A monoprotic acid (HA) is 1% ionised in ...

A monoprotic acid `(HA)` is `1%` ionised in its aqueous solution of `0.1M` strength. Its `pOH` will be

A

11

B

3

C

10

D

2

Text Solution

Verified by Experts

The correct Answer is:
A
`[H_(2)O^(+)]=c alpha =0.1 xx (0.01)=1xx10^(-3)`
`:. pH=3` . Hence, `pOH =14-3=11`.
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