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pK(b) of NH(3) is 4.74. The pH when 100 ...

`pK_(b)` of `NH_(3)` is 4.74. The pH when 100 mL of 0.01 M `NH_(3)` solution is 50% neutralised by 0.01 M HCl is

A

4.74

B

2.37

C

9.26

D

9.48

Text Solution

Verified by Experts

The correct Answer is:
C

At `50%` neutralisation
`[NH_(4)^(+)]=[NH_(3)]`
The solution is a buffer
`:. pOH =pK_(b)+log.([NH_(4)^(+)])/([NH_(3)])`
`4.74+log 1 =4.74`
`pH =14-4=9.26`
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DINESH PUBLICATION-IONIC EQUILIBRIUM -MULTIPLE CHOICE QUESTIONS
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  16. BOH is a weak base, molar concentration of BOH that provides a [OH]^(-...

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