Home
Class 12
CHEMISTRY
pH of 0.01 M (NH(4))(2) SO(4) and 0.02 M...

pH of 0.01 M `(NH_(4))_(2) SO_(4)` and 0.02 M `NH_(4)OH` buffer `(pK_(a)` of `NH_(4)^(+)=9.26)` is

A

`4.74+log 2 `

B

`4.74 -log2`

C

`9.26+log 2`

D

`9.26+log 1`

Text Solution

Verified by Experts

The correct Answer is:
D
`pK_(a)(NH_(4)^(+))=9.26`
`pK_(b)(NH_(3))=14-9.26=4.74`
`[NH_(4)]=2xx[(NH_(4))_(2)SO_(4)]`
`=2xx0.01=0.02 M`
`pOH =pK_(b)+log . ([NH_(4)^(+)])/([NH_(4)OH])`
`pOH =4.74 +log . (0.02)/(0.02)=4.74-log 1`
`pH =14-pOH =1404.74+log 1`
`=9.26+log 1`
Promotional Banner

Topper's Solved these Questions

  • IONIC EQUILIBRIUM

    DINESH PUBLICATION|Exercise REVISION QUESTIONS FROM COMPETITVE EXAMS|236 Videos

  • IONIC EQUILIBRIUM

    DINESH PUBLICATION|Exercise SELECTED STRAIGHT OBJECTIVE TYPE MCQs|10 Videos

  • IONIC EQUILIBRIUM

    DINESH PUBLICATION|Exercise Buffer solutions / Salt Hydrolysis|29 Videos

  • HYDROCARBONS

    DINESH PUBLICATION|Exercise All Questions|493 Videos

  • NO IDEA

    DINESH PUBLICATION|Exercise Unit Test -|1 Videos

Similar Questions

Explore conceptually related problems

The pH of basic buffer mixtures is given by : pH=pK_(a)+log((["Base"])/(["Salt"])) , whereas pH of acidic buffer mixtures is given by: pH= pK_(a)+log((["Salt"])/(["Acid"])) . Addition of little acid or base although shows no appreciable change for all practical purpose, but since the ratio (["Base"])/(["Salt"]) or (["Salt"])/(["Acid"]) change, a slight decrease or increase in pH results in. The amount of (NH_(4))_(2)SO_(4) to be added to 500 mL of 0.01M NH_(4)OH solution (pK_(a) for NH_(4)^(+) is 9.26) prepare a buffer of pH 8.26 is:

To prepare a buffer of pH 8.26 , amount of (NH_(4))_(2)SO_(4) to be added into 500mL of 0.01M NH_(4)OH solution [pK_(a)(NH_(4)^(+))=9.26] is:

The Ph of basic buffer mixtures is given by : Ph=Pk_(a)+ log (["Base"])/(["Salt"]) whereas Ph of acidic buffer mixtures is given by : Ph = pK_(a)+"log"(["Salt"])/(["Acid"]) . Addition of little acid or base although shows no appreciable change in Ph for all practical purposes, but sicne the ratio (["Base"])/(["Salt"]) or (["Salt"])/(["Acid"]) changes, a slight decrease or increase in pH results. The amount of (NH_(4))_(2)SO_(4) to be added to 500mL of 0.01 M NH_(4)OH solution (pH_(a)NH_(4)^(+) is 9.26) to prepare a buffer of pH 8.26 is :

What is the pH of solution obtained by mixing 100 mL of each 0.2 M NH_(4)Cl and 0.2M NH_(4)OH , if pK_(b) of NH_(4)OH is 4.2 ?

What is the pH of solution obtained by mixing 100 mL of each 0.2 M NH_(4)Cl and 0.2M NH_(4)OH , if pK_(b) of NH_(4)OH is 4.2 ?

A solution consist of 0.2 M NH_(4)OH and 0.2 M NH_(4)Cl . If K_(b) of NH_(4)OH is 1.8 xx 10^(-5) , the [OH^(-)] of the resulting is

DINESH PUBLICATION-IONIC EQUILIBRIUM -MULTIPLE CHOICE QUESTIONS
  1. pH of the solution containing 50.0 mL of 0.3 M HCl and 50.0 mL of 0.4 ...

    Text Solution

    |

  2. pH at which an acidic indicator with K("in")=1xx10^(-5) changes colour...

    Text Solution

    |

  3. pH at which a basic indicator with K("in")=1xx10^(-10) changes colour ...

    Text Solution

    |

  4. A weak base, B, has basicity constant K(b)=2xx10^(-5). The pH of any s...

    Text Solution

    |

  5. pH of 0.01 M (NH(4))(2) SO(4) and 0.02 M NH(4)OH buffer (pK(a) of NH(4...

    Text Solution

    |

  6. 100mL of pH =6 solution is diluted to 100mL by water. pH of the soluti...

    Text Solution

    |

  7. Auto-ionisation of liquid NH(3) is 2NH(3) hArr NH(4)^(o+) +NH(2)^(Th...

    Text Solution

    |

  8. BOH is a weak base, molar concentration of BOH that provides a [OH]^(-...

    Text Solution

    |

  9. Which of the following solution will have pH of 4.74

    Text Solution

    |

  10. Which of the following mixtures will act as a buffer solution when dis...

    Text Solution

    |

  11. For the reaction S(2)O(3)^(2-)(aq) +2H(3)O^(+)(aq) hArr S(s)+H(2)SO(...

    Text Solution

    |

  12. Both HCOOH and CH(3)COOH solutions have equal pH. If K(1) // K(2) ( r...

    Text Solution

    |

  13. pH of Ca(OH)(2) solution is 12. Millimoles of Ca(OH)(2) present in 100...

    Text Solution

    |

  14. A buffer solution contains 100mL of 0.01 M CH(3)COOH and 200mL of 0.02...

    Text Solution

    |

  15. Assuming 100% ionization in case of strong electrolytes which of the f...

    Text Solution

    |

  16. To prepare a buffer of pH 8.26, amount of (NH(4))(2)SO(4) to be added ...

    Text Solution

    |

  17. Percentange ionisation of weak acid can be calculated using the formul...

    Text Solution

    |

  18. pH of a mixture of 1 M benzoic acid (pK(a)=4.20) and 1 M C(6)H(5)COONa...

    Text Solution

    |

  19. If the freezing point of 0.1 M HA(aq) solution is -0.2046^(@)C then pH...

    Text Solution

    |

  20. If the equilibrium constant for the reaction of weak acid HA with stro...

    Text Solution

    |