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A weak acid, HA, has a K(a) of 1.00xx10^...

A weak acid, HA, has a `K_(a)` of `1.00xx10^(-5)`. If `0.100` mol of the acid is dissolved in 1 L of water, the percentage of the acid dissociated at equilibrium is the closed to

A

`0.100%`

B

`99.0%`

C

`1.00%`

D

`99.9%`

Text Solution

Verified by Experts

The correct Answer is:
C
For a weak monobasic acid
`K_(a)=c alpha^(2)`
`alph =sqrt((K_(a))/(c ))=sqrt((1.00 xx 10^(-5))/(0.100))`
`=sqrt(1.00 xx 10^(-4))=10^(-2)`
`% alpha =100%`
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