In a closed vessel of volume v, a moles of nitrogen and b moles of oxygen are made to react to given nitric oxide, according to reaction , `N_(2)+O_(2) hArr 2NO`. If at equilibrium , 2x moles of NO are obtained , then

Options

A. `K_(c )=(x^(2))/((a-x)(b-x)).v`
B. `K_(c )=(4x^(2))/((a-x)(b-x)).v`
C. `K_(c )=(4x^(2))/((a-x)(b-x)).(1)/(v)`
D. `K_(c )=(4x^(2))/((a-x)(b-x))`

Answer

D

Explanation

For reaction
`{:(,N_(2),+,O_(2),2NO),("Eqbm. conc.",a-x,,b-x,2x):}`
Thus, `K_(c)=([NO]^(2))/([N_(2)][O_(2)])=((2x)^(2))/((a-x)(b-x))`
`=(4x^(2))/((a-x)(b-x))`