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The pH of a solution obtaine by mixing 5...

The pH of a solution obtaine by mixing `50 mL` of `0.4 N HCl` and `50 mL` of `0.2 N NaOH` is

A

log 2

B

`1.0`

C

`-log (0.05)`

D

`2.0`

Text Solution

Verified by Experts

The correct Answer is:
B
Acid left unconsumed `=(50 xx 0.2)/( 0.4)`
`=25 mL ` fo `0.4 N`
New normality of resulting solution
`=25 xx 0.4 -= 100xx N =0.1 N`
`pH =-log [10^(-1)]=1`
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DINESH PUBLICATION-IONIC EQUILIBRIUM -BRAIN TEASERS -3
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