What is the work done when 1.0 mole of an ideal gas expands from 10 atmosphere to 2 atmosphere in one step at 300K ?

Options

A. `-2.303 nRT log P_(1)//P_(2)`
B. `-60R`
C. `-2 xx 1.0 xx 300 R xx (2)/(5)`
D. `-120 R`

Answer

C

Explanation

`W=-P_("ext")(V_(2)-V_(1))` is the expression used for irreversible work i.e., work donw in one step . As the volume is not given
`:. V_(2)=(nRT)/(P_(2))` and `V_(1)=(nRT)/(P_(1))`
or `W=-P_("ext")((1)/(P_(2))-(1)/(P_(1)))`
`n=1.0 R,T=300K,`
`(1)/(P_(2))-(1)/(P_(1))=(2)/(5),P_("ext")=2 atm`
`:. W=-2 xx 1.0 xx R xx 300xx(2)/(5)=-240R`