Blue litmus turns red in the following mixture of acid and base

Options

A. 100 mL of `1 xx 10^(-2) M H_(2)SO_(4)+` 100mL of `1 xx 10^(-2)M Ca(OH)_(2)`
B. 100 mL of `1 xx 10^(-2) M HCl + ` 100 mL of `1 xx 10^(-2) M Ba(OH)_(2)`
C. 100 mL of `1 xx 10^(-2)` M `H_(2)SO_(4) +` 100 mL of `1 xx 10^(-2)` M NaOH
D. 100 mL of `1 xx 10^(-2)` M HCl `+` 100 mL of `1 xx 10^(-2)` M NaOH

Answer

C

Explanation

Blue litmus turn red if mixture is acidic that is in which moles of `H^(+) gt ` moles of `OH^(-)`
(A) Moles of `H^(+)=(100 xx 10^(-3)L)(2 xx 10^(-2)mol L^(-1))`
`= 2 xx 10^(-3) mol`
`(1` mol `H_(2)SO_(4)-= 2 mol H^(+))`
Moles of `OH^(-)=(100 xx 10^(-3)L)xx(2 xx 10^(-2)mol H^(+))`
`=2 xx 10^(-3)mol`
`(1 ` mol `Ca(OH)_(2)-=2 mol OH^(-))`
The resulting solution will be neutral because moles of `H^(+)=` moles of `OH^(-)`
`(B)` Moles of `H^(+)=(100 xx 10^(-3)L)XX(10^(-2)mol L^(-1))`
`=10^(-3)mol `
`(1 ` mol `HCl-=1 mol H^(+))`
Mole of `OH^(-) =(100 xx 10^(-3)L)xx(2 xx 10^(-2)mol H^(+))`
The resulting solution will be alkaline because moles of `H^(+) lt` moles of `OH^(-)`
`(C )` Moles of `H^(+)`
`=(100 xx 10^(-3)L)xx(2 xx 10^(-2) mol L^(-1))`
`=2 xx 10^(-3) mol `
Moles of `OH^(-)`
`=(100 xx 10^(-3)L)xx(1 xx 10^(-2) mol L^(-1))`
`10^(-3)mol`
The resulting solution will be acidic because moles of `H^(+) gt ` moles of `H^(+)`
Thus choice `(C )` is correct
`(D )` Moles of `H^(+)`
`=(100 xx 10^(-3)L) xx (1xx 10^(-2) mol L^(-1) )`
`=10^(-3)mol`
Moles of `OH^(-)`
`=(100 xx 10^(-3)L)xx(1 xx 10^(-2) mol L^(-1))`
`=10^(-3) mol`
The resulting solution will e neutral because moles of `H^(+) =` moles of `OH^(-)`