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pH of a mixture which is 0. 1 M in CH(3)...

pH of a mixture which is 0. 1 M in `CH_(3)COOH` and 0.05 M in `(CH_(3)COOH)_(2)Ba` is `[pK_(a)` of `CH_(3)COOH=4.74]`

A

4.74

B

5.04

C

4.44

D

`7.00`

Text Solution

Verified by Experts

The correct Answer is:
A
`[CH_(3)COO^(-)]=2[(CH_(3)COO)_(2)Ba]`
`=2 xx 0.05 =0.1 M`
`[CH_(3)COOH]=0.1M`
`pH=pK_(a)+log.(["Salt"])/(["Acid"])`
`=4.74 +log.(0.1)/(0.1)=4.74`
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