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For the following equilibrium PCl(5)(g...

For the following equilibrium
`PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g)`
`K_(p)` is formed to be equal to `K_(x )`. This is attained at

A

1 atm

B

0.5 atm

C

2 atm

D

4 atm

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(p)=K_(x )(P)^(Deltan)`
`K_(x)` is equilibrium constant when concentration are take as mole fraction.
`K_(p)=K_(x)(P)`
`K_(p)=K_(x)` when `P=1` atm
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