A mixture of `NH_(4)Cl` and `I_(2)` can be separated by

Options

A. Fractional crystallisation
B. Extraction with water
C. Sublimation
D. Chromatography

Explanation

To solve the problem of separating a mixture of ammonium chloride (NH₄Cl) and iodine (I₂), we can follow these steps:

### Step 1: Understand the Properties of the Components
- **Ammonium Chloride (NH₄Cl)**: This is an ionic compound that is soluble in water.
- **Iodine (I₂)**: This is a molecular solid that is not soluble in water at room temperature.

### Step 2: Choose a Separation Method
Given the properties of NH₄Cl and I₂, we need to select a separation method that takes advantage of their differing solubilities in water.

### Step 3: Use Water for Extraction
- Since NH₄Cl is soluble in water, we can add water to the mixture.
- The NH₄Cl will dissolve in the water, while the I₂ will remain undissolved.

### Step 4: Filter the Mixture
- After adding water, we can filter the mixture.
- The solid residue left on the filter paper will be I₂, while the NH₄Cl will be in the filtrate (the liquid that passes through the filter).

### Step 5: Evaporate the Filtrate
- To recover NH₄Cl from the filtrate, we can evaporate the water.
- This will leave behind solid NH₄Cl.

### Final Result
- We will have separated the mixture into solid iodine (I₂) and solid ammonium chloride (NH₄Cl).

### Conclusion
The correct method to separate a mixture of NH₄Cl and I₂ is by **extraction with water**.

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