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Hydrogen and oxygen combine to form H(2)...

Hydrogen and oxygen combine to form `H_(2)O_(2)` and `H_(2)O` containing `5.93 %` and `11.2%` hydrogen respectively. The data illustrates

A

Law of conservation of mass

B

Law of constant proportion

C

Law of reciprocal proportions

D

Law of multiple proportions

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To solve the question, we will analyze the percentages of hydrogen in the compounds \( H_2O_2 \) and \( H_2O \) and determine which law of chemical proportions they illustrate. ### Step 1: Calculate the mass percentages of hydrogen in \( H_2O_2 \) and \( H_2O \) 1. **For \( H_2O_2 \)**: - The molar mass of \( H_2O_2 \) is \( 2(1) + 2(16) = 34 \, g/mol \). - The mass percentage of hydrogen in \( H_2O_2 \) is given as \( 5.93\% \). 2. **For \( H_2O \)**: - The molar mass of \( H_2O \) is \( 2(1) + 16 = 18 \, g/mol \). - The mass percentage of hydrogen in \( H_2O \) is given as \( 11.2\% \). ### Step 2: Convert mass percentages to a simple ratio 1. **Convert percentages to mass ratios**: - For \( H_2O_2 \): - Hydrogen: \( 5.93 \, g \) - Oxygen: \( 100 - 5.93 = 94.07 \, g \) - For \( H_2O \): - Hydrogen: \( 11.2 \, g \) - Oxygen: \( 100 - 11.2 = 88.8 \, g \) ### Step 3: Establish a ratio of hydrogen to oxygen 1. **Calculate the ratio of hydrogen to oxygen**: - For \( H_2O_2 \): - Ratio of \( H:O = 5.93:94.07 \) - For \( H_2O \): - Ratio of \( H:O = 11.2:88.8 \) ### Step 4: Simplify the ratios 1. **Simplify the ratios**: - For \( H_2O_2 \): - \( 5.93:94.07 \) simplifies to approximately \( 1:15.85 \) - For \( H_2O \): - \( 11.2:88.8 \) simplifies to approximately \( 1:7.93 \) ### Step 5: Compare the ratios 1. **Determine the ratio of hydrogen in both compounds**: - The ratio of hydrogen in \( H_2O_2 \) to hydrogen in \( H_2O \) can be expressed as: - \( \frac{5.93}{11.2} \) which gives us a ratio of approximately \( 0.529 \). ### Step 6: Identify the law illustrated 1. **Identify the law of multiple proportions**: - The ratios of the masses of hydrogen that combine with a fixed mass of oxygen (from both compounds) demonstrate that the amounts of hydrogen that combine with the same amount of oxygen are in a simple ratio. - This illustrates the **Law of Multiple Proportions**, which states that when two elements combine to form more than one compound, the ratios of the masses of one element that combine with a fixed mass of the other element are in simple whole number ratios. ### Conclusion The data illustrates the **Law of Multiple Proportions**.

To solve the question, we will analyze the percentages of hydrogen in the compounds \( H_2O_2 \) and \( H_2O \) and determine which law of chemical proportions they illustrate. ### Step 1: Calculate the mass percentages of hydrogen in \( H_2O_2 \) and \( H_2O \) 1. **For \( H_2O_2 \)**: - The molar mass of \( H_2O_2 \) is \( 2(1) + 2(16) = 34 \, g/mol \). - The mass percentage of hydrogen in \( H_2O_2 \) is given as \( 5.93\% \). ...
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