Two elements X (atomic mass 16) and Y(atomic mass 14) combine to form compounds A,B and C. The ratio of different masses of Y which combine with a fixed mass of X in A,B and C is 1:3:5. If 32 parts by mass of X combines with 84 parts by mass of Y in B, then in C, 16 parts by mass of X will combine with :

Options

A. 14 parts by mass of Y
B. 42 parts by mass of Y
C. 70 parts by mass of Y
D. 84 parts by mass Y

Answer

C

Explanation

In B, 32 parts of X combines with Y = 84 parts
`:.` 16 parts of X will combine with Y = 42 parts
Now number of parts of X in both B and C is equal.
Different masses of Y which combine with a fixed mass of X in B and C are in the ratio 3:5
`:. ("Mass of Y in B")/("Mass of Y in C")=(3)/(5)`
`(42parts)/("Mass of Y in C")=(3)/(5)`
`:.` Mass of Y in C `=(5)/(3)xx42=70` parts.