The number of sodium atoms in 2 moles of sodium ferrocyanide is

Options

A. `2`
B. `6*02xx10^(23)`
C. `8xx6*02xx10^(23)`
D. `4xx6*02xx10^(23)`

Explanation

To find the number of sodium atoms in 2 moles of sodium ferrocyanide (Na₄[Fe(CN)₆]), we can follow these steps:

### Step 1: Identify the formula of sodium ferrocyanide
The formula for sodium ferrocyanide is Na₄[Fe(CN)₆]. This indicates that each formula unit of sodium ferrocyanide contains 4 sodium (Na) atoms.

### Step 2: Determine the number of moles of sodium in 2 moles of sodium ferrocyanide
Since each mole of sodium ferrocyanide contains 4 moles of sodium, in 2 moles of sodium ferrocyanide, the number of moles of sodium can be calculated as follows:
\[ \text{Number of moles of sodium} = 2 \, \text{moles of Na₄[Fe(CN)₆]} \times 4 \, \text{moles of Na per mole of Na₄[Fe(CN)₆]} = 8 \, \text{moles of Na} \]

### Step 3: Calculate the number of sodium atoms
To find the total number of sodium atoms, we use Avogadro's number, which is approximately \(6.02 \times 10^{23}\) atoms/mole. Therefore, the total number of sodium atoms in 8 moles of sodium is:
\[ \text{Number of sodium atoms} = 8 \, \text{moles of Na} \times 6.02 \times 10^{23} \, \text{atoms/mole} = 8 \times 6.02 \times 10^{23} \, \text{atoms} \]

### Final Answer
Thus, the number of sodium atoms in 2 moles of sodium ferrocyanide is:
\[ 8 \times 6.02 \times 10^{23} \, \text{atoms} \]