Total number of atoms in 44 g `CO_(2)` is

Options

A. `6*02xx10^(23)`
B. `6*02xx10^(24)`
C. `1*806xx10^(22)`
D. `18*06xx10^(22)`.

Answer

C

Explanation

Total no. of moles of `CO_(2)` in 44 g `= (44)/(44) = 1`
1 mole `CO_(2)` = 1 mole C + 2 mole O atoms
= 3 mole atom
`= 3xx6*02xx10^(23) = 1*806xx10^(24)`