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NO reacts with O(2) to form NO(2). When ...

NO reacts with `O_(2)` to form `NO_(2)`. When 10 g of `NO_(2)` is formed during the reaction, the mass of `O_(2)` consumed is

A

`1*90 g`

B

`5*0 g`

C

`3*48 g`

D

`13*9 g`

Text Solution

Verified by Experts

The correct Answer is:
C
`2NO+underset(32g)(O_(2))tounderset(2xx46g)(2NO_(2))`
`92 g NO_(2)` uses `O_(2) = 32g`
`:. 10 g NO_(2)` uses `O_(2) = (32)/(92)xx10=3*48g`
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