In a certain reaction ferrous oxalate is oxidised to ferric sulphate and `CO_(2)` by acidified potassium permanganate, the equivalent mass of ferrous oxalate is

Options

A. `("Mol. mass")/(3)`
B. `("Mol. mass")/(1)`
C. `("Mol. mass")/(2)`
D. `("Mol. mass")/(0*5)`

Answer

A

Explanation

`overset(+2)(Fe)(overset(+3)(C_(2))O_(4))overset(-3e^(-)" ")(to)overset(+3)(F)e^(3+)+2overset(+4)(C)O_(2)`
Since one molecule loses `3e^(-)`
Thus, Eq. mass `= ("Mol. mass")/(3)`